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2x-5(x-4)=-2+3x+10
We move all terms to the left:
2x-5(x-4)-(-2+3x+10)=0
We add all the numbers together, and all the variables
2x-5(x-4)-(3x+8)=0
We multiply parentheses
2x-5x-(3x+8)+20=0
We get rid of parentheses
2x-5x-3x-8+20=0
We add all the numbers together, and all the variables
-6x+12=0
We move all terms containing x to the left, all other terms to the right
-6x=-12
x=-12/-6
x=+2
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