2x-5(x-4)=-9+3x-19

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Solution for 2x-5(x-4)=-9+3x-19 equation:



2x-5(x-4)=-9+3x-19
We move all terms to the left:
2x-5(x-4)-(-9+3x-19)=0
We add all the numbers together, and all the variables
2x-5(x-4)-(3x-28)=0
We multiply parentheses
2x-5x-(3x-28)+20=0
We get rid of parentheses
2x-5x-3x+28+20=0
We add all the numbers together, and all the variables
-6x+48=0
We move all terms containing x to the left, all other terms to the right
-6x=-48
x=-48/-6
x=+8

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