2x-5(x-5)=-7+3x+20

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Solution for 2x-5(x-5)=-7+3x+20 equation: 



2x-5(x-5)=-7+3x+20

We move all terms to the left:

2x-5(x-5)-(-7+3x+20)=0

We add all the numbers together, and all the variables

2x-5(x-5)-(3x+13)=0

We multiply parentheses

2x-5x-(3x+13)+25=0

We get rid of parentheses

2x-5x-3x-13+25=0

We add all the numbers together, and all the variables

-6x+12=0

We move all terms containing x to the left, all other terms to the right

-6x=-12

x=-12/-6

x=+2

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