2x-5+x=4(x-3)+x

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Solution for 2x-5+x=4(x-3)+x equation: 



2x-5+x=4(x-3)+x

We move all terms to the left:

2x-5+x-(4(x-3)+x)=0

We add all the numbers together, and all the variables

3x-(4(x-3)+x)-5=0



We calculate terms in parentheses: -(4(x-3)+x), so:

4(x-3)+x

We add all the numbers together, and all the variables

x+4(x-3)

We multiply parentheses

x+4x-12

We add all the numbers together, and all the variables

5x-12

Back to the equation:

-(5x-12)



We get rid of parentheses

3x-5x+12-5=0

We add all the numbers together, and all the variables

-2x+7=0

We move all terms containing x to the left, all other terms to the right

-2x=-7

x=-7/-2

x=3+1/2

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