2x-5-(4x-1)=3x+2(7-2x)+1

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Solution for 2x-5-(4x-1)=3x+2(7-2x)+1 equation: 



2x-5-(4x-1)=3x+2(7-2x)+1

We move all terms to the left:

2x-5-(4x-1)-(3x+2(7-2x)+1)=0

We add all the numbers together, and all the variables

2x-(4x-1)-(3x+2(-2x+7)+1)-5=0

We get rid of parentheses

2x-4x-(3x+2(-2x+7)+1)+1-5=0



We calculate terms in parentheses: -(3x+2(-2x+7)+1), so:

3x+2(-2x+7)+1

We multiply parentheses

3x-4x+14+1

We add all the numbers together, and all the variables

-1x+15

Back to the equation:

-(-1x+15)



We add all the numbers together, and all the variables

-2x-(-1x+15)-4=0

We get rid of parentheses

-2x+1x-15-4=0

We add all the numbers together, and all the variables

-1x-19=0

We move all terms containing x to the left, all other terms to the right

-x=19

x=19/-1

x=-19

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