2x-5/3x+1/7x=10

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Solution for 2x-5/3x+1/7x=10 equation: 



2x-5/3x+1/7x=10

We move all terms to the left:

2x-5/3x+1/7x-(10)=0



Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R





Domain of the equation: 7x!=0

x!=0/7

x!=0

x∈R



We calculate fractions


2x+(-35x)/21x^2+3x/21x^2-10=0

We multiply all the terms by the denominator


2x*21x^2+(-35x)+3x-10*21x^2=0

We add all the numbers together, and all the variables

3x+2x*21x^2+(-35x)-10*21x^2=0

Wy multiply elements

42x^3-210x^2+3x+(-35x)=0

We get rid of parentheses

42x^3-210x^2+3x-35x=0

We do not support expression: x^3

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