2x-5/4x-7=x+3/2x+5

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Solution for 2x-5/4x-7=x+3/2x+5 equation: 



2x-5/4x-7=x+3/2x+5

We move all terms to the left:

2x-5/4x-7-(x+3/2x+5)=0



Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R





Domain of the equation: 2x+5)!=0

x∈R



We get rid of parentheses

2x-5/4x-x-3/2x-5-7=0

We calculate fractions


2x-x+(-10x)/8x^2+(-12x)/8x^2-5-7=0

We add all the numbers together, and all the variables

x+(-10x)/8x^2+(-12x)/8x^2-12=0

We multiply all the terms by the denominator


x*8x^2+(-10x)+(-12x)-12*8x^2=0

Wy multiply elements

8x^3-96x^2+(-10x)+(-12x)=0

We get rid of parentheses

8x^3-96x^2-10x-12x=0

We do not support expression: x^3

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