2x-5/x-3=4x+1/2x

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Solution for 2x-5/x-3=4x+1/2x equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

2*x-(5/x)-3 = 4*x+(1/2)*x // - 4*x+(1/2)*x

2*x-(4*x)-((1/2)*x)-(5/x)-3 = 0

2*x-4*x+(-1/2)*x-5*x^-1-3 = 0

-5/2*x^1-5*x^-1-3*x^0 = 0

(-5/2*x^2-3*x^1-5*x^0)/(x^1) = 0 // * x^2

x^1*(-5/2*x^2-3*x^1-5*x^0) = 0

x^1

(-5/2)*x^2-3*x-5 = 0

(-5/2)*x^2-3*x-5 = 0

DELTA = (-3)^2-(-5*4*(-5/2))

DELTA = -41

DELTA < 0

x in { } 

x belongs to the empty set

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