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2x-5/x=99
We move all terms to the left:
2x-5/x-(99)=0
Domain of the equation: x!=0We multiply all the terms by the denominator
x∈R
2x*x-99*x-5=0
We add all the numbers together, and all the variables
-99x+2x*x-5=0
Wy multiply elements
2x^2-99x-5=0
a = 2; b = -99; c = -5;
Δ = b2-4ac
Δ = -992-4·2·(-5)
Δ = 9841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-99)-\sqrt{9841}}{2*2}=\frac{99-\sqrt{9841}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-99)+\sqrt{9841}}{2*2}=\frac{99+\sqrt{9841}}{4} $
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