2x-5/x=x-3/2

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Solution for 2x-5/x=x-3/2 equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

2*x-(5/x) = x-(3/2) // - x-(3/2)

2*x-x-(5/x)+3/2 = 0

2*x-x-5*x^-1+3/2 = 0

1*x^1-5*x^-1+3/2*x^0 = 0

(1*x^2+3/2*x^1-5*x^0)/(x^1) = 0 // * x^2

x^1*(1*x^2+3/2*x^1-5*x^0) = 0

x^1

x^2+(3/2)*x-5 = 0

x^2+(3/2)*x-5 = 0

DELTA = (3/2)^2-(-5*1*4)

DELTA = 89/4

DELTA > 0

x = ((89/4)^(1/2)-(3/2))/(1*2) or x = (-(3/2)-(89/4)^(1/2))/(1*2)

x = ((89/4)^(1/2)-3/2)/2 or x = (-((89/4)^(1/2)+3/2))/2

x in { (-((89/4)^(1/2)+3/2))/2, ((89/4)^(1/2)-3/2)/2}

x in { (-((89/4)^(1/2)+3/2))/2, ((89/4)^(1/2)-3/2)/2 }

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