2x-5=(7x+1)2

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Solution for 2x-5=(7x+1)2 equation: 



2x-5=(7x+1)2

We move all terms to the left:

2x-5-((7x+1)2)=0



We calculate terms in parentheses: -((7x+1)2), so:

(7x+1)2

We multiply parentheses

14x+2

Back to the equation:

-(14x+2)



We get rid of parentheses

2x-14x-2-5=0

We add all the numbers together, and all the variables

-12x-7=0

We move all terms containing x to the left, all other terms to the right

-12x=7

x=7/-12

x=-7/12

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