2x-5=2(3x-8)+7x

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Solution for 2x-5=2(3x-8)+7x equation:



2x-5=2(3x-8)+7x
We move all terms to the left:
2x-5-(2(3x-8)+7x)=0
We calculate terms in parentheses: -(2(3x-8)+7x), so:
2(3x-8)+7x
We add all the numbers together, and all the variables
7x+2(3x-8)
We multiply parentheses
7x+6x-16
We add all the numbers together, and all the variables
13x-16
Back to the equation:
-(13x-16)
We get rid of parentheses
2x-13x+16-5=0
We add all the numbers together, and all the variables
-11x+11=0
We move all terms containing x to the left, all other terms to the right
-11x=-11
x=-11/-11
x=1

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