2x-5=3(1-x)+22

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Solution for 2x-5=3(1-x)+22 equation: 



2x-5=3(1-x)+22

We move all terms to the left:

2x-5-(3(1-x)+22)=0

We add all the numbers together, and all the variables

2x-(3(-1x+1)+22)-5=0



We calculate terms in parentheses: -(3(-1x+1)+22), so:

3(-1x+1)+22

We multiply parentheses

-3x+3+22

We add all the numbers together, and all the variables

-3x+25

Back to the equation:

-(-3x+25)



We get rid of parentheses

2x+3x-25-5=0

We add all the numbers together, and all the variables

5x-30=0

We move all terms containing x to the left, all other terms to the right

5x=30

x=30/5

x=6

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