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2x-5=5x(6+9x)
We move all terms to the left:
2x-5-(5x(6+9x))=0
We add all the numbers together, and all the variables
2x-(5x(9x+6))-5=0
We calculate terms in parentheses: -(5x(9x+6)), so:We get rid of parentheses
5x(9x+6)
We multiply parentheses
45x^2+30x
Back to the equation:
-(45x^2+30x)
-45x^2+2x-30x-5=0
We add all the numbers together, and all the variables
-45x^2-28x-5=0
a = -45; b = -28; c = -5;
Δ = b2-4ac
Δ = -282-4·(-45)·(-5)
Δ = -116
Delta is less than zero, so there is no solution for the equation
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