2x-5=6(x+1)+11x+6

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Solution for 2x-5=6(x+1)+11x+6 equation: 



2x-5=6(x+1)+11x+6

We move all terms to the left:

2x-5-(6(x+1)+11x+6)=0



We calculate terms in parentheses: -(6(x+1)+11x+6), so:

6(x+1)+11x+6

We add all the numbers together, and all the variables

11x+6(x+1)+6

We multiply parentheses

11x+6x+6+6

We add all the numbers together, and all the variables

17x+12

Back to the equation:

-(17x+12)



We get rid of parentheses

2x-17x-12-5=0

We add all the numbers together, and all the variables

-15x-17=0

We move all terms containing x to the left, all other terms to the right

-15x=17

x=17/-15

x=-1+2/15

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