2x-6(3x-8)+7/4=12

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Solution for 2x-6(3x-8)+7/4=12 equation:



2x-6(3x-8)+7/4=12
We move all terms to the left:
2x-6(3x-8)+7/4-(12)=0
determiningTheFunctionDomain 2x-6(3x-8)-12+7/4=0
We multiply parentheses
2x-18x+48-12+7/4=0
We multiply all the terms by the denominator
2x*4-18x*4+7+48*4-12*4=0
We add all the numbers together, and all the variables
2x*4-18x*4+151=0
Wy multiply elements
8x-72x+151=0
We add all the numbers together, and all the variables
-64x+151=0
We move all terms containing x to the left, all other terms to the right
-64x=-151
x=-151/-64
x=2+23/64

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