2x-6+2(3x+1)=-4(x+2)

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Solution for 2x-6+2(3x+1)=-4(x+2) equation:



2x-6+2(3x+1)=-4(x+2)
We move all terms to the left:
2x-6+2(3x+1)-(-4(x+2))=0
We multiply parentheses
2x+6x-(-4(x+2))+2-6=0
We calculate terms in parentheses: -(-4(x+2)), so:
-4(x+2)
We multiply parentheses
-4x-8
Back to the equation:
-(-4x-8)
We add all the numbers together, and all the variables
8x-(-4x-8)-4=0
We get rid of parentheses
8x+4x+8-4=0
We add all the numbers together, and all the variables
12x+4=0
We move all terms containing x to the left, all other terms to the right
12x=-4
x=-4/12
x=-1/3

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