2x-6+35x=67(x+3)

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Solution for 2x-6+35x=67(x+3) equation: 



2x-6+35x=67(x+3)

We move all terms to the left:

2x-6+35x-(67(x+3))=0

We add all the numbers together, and all the variables

37x-(67(x+3))-6=0



We calculate terms in parentheses: -(67(x+3)), so:

67(x+3)

We multiply parentheses

67x+201

Back to the equation:

-(67x+201)



We get rid of parentheses

37x-67x-201-6=0

We add all the numbers together, and all the variables

-30x-207=0

We move all terms containing x to the left, all other terms to the right

-30x=207

x=207/-30

x=-6+9/10

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