2x-7(3x+11)=56

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Solution for 2x-7(3x+11)=56 equation: 



2x-7(3x+11)=56

We move all terms to the left:

2x-7(3x+11)-(56)=0

We multiply parentheses

2x-21x-77-56=0

We add all the numbers together, and all the variables

-19x-133=0

We move all terms containing x to the left, all other terms to the right

-19x=133

x=133/-19

x=-7

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