2x-7+3(3x+3)=-7(x+1)

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Solution for 2x-7+3(3x+3)=-7(x+1) equation: 



2x-7+3(3x+3)=-7(x+1)

We move all terms to the left:

2x-7+3(3x+3)-(-7(x+1))=0

We multiply parentheses

2x+9x-(-7(x+1))+9-7=0



We calculate terms in parentheses: -(-7(x+1)), so:

-7(x+1)

We multiply parentheses

-7x-7

Back to the equation:

-(-7x-7)



We add all the numbers together, and all the variables

11x-(-7x-7)+2=0

We get rid of parentheses

11x+7x+7+2=0

We add all the numbers together, and all the variables

18x+9=0

We move all terms containing x to the left, all other terms to the right

18x=-9

x=-9/18

x=-1/2

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