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2x-7/x+3=0
Domain of the equation: x!=0We multiply all the terms by the denominator
x∈R
2x*x+3*x-7=0
We add all the numbers together, and all the variables
3x+2x*x-7=0
Wy multiply elements
2x^2+3x-7=0
a = 2; b = 3; c = -7;
Δ = b2-4ac
Δ = 32-4·2·(-7)
Δ = 65
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{65}}{2*2}=\frac{-3-\sqrt{65}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{65}}{2*2}=\frac{-3+\sqrt{65}}{4} $
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