2x-8(3x-12)=20

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Solution for 2x-8(3x-12)=20 equation: 



2x-8(3x-12)=20

We move all terms to the left:

2x-8(3x-12)-(20)=0

We multiply parentheses

2x-24x+96-20=0

We add all the numbers together, and all the variables

-22x+76=0

We move all terms containing x to the left, all other terms to the right

-22x=-76

x=-76/-22

x=3+5/11

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