2x-8(x+1)=2(3x-2)+3x

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Solution for 2x-8(x+1)=2(3x-2)+3x equation: 



2x-8(x+1)=2(3x-2)+3x

We move all terms to the left:

2x-8(x+1)-(2(3x-2)+3x)=0

We multiply parentheses

2x-8x-(2(3x-2)+3x)-8=0



We calculate terms in parentheses: -(2(3x-2)+3x), so:

2(3x-2)+3x

We add all the numbers together, and all the variables

3x+2(3x-2)

We multiply parentheses

3x+6x-4

We add all the numbers together, and all the variables

9x-4

Back to the equation:

-(9x-4)



We add all the numbers together, and all the variables

-6x-(9x-4)-8=0

We get rid of parentheses

-6x-9x+4-8=0

We add all the numbers together, and all the variables

-15x-4=0

We move all terms containing x to the left, all other terms to the right

-15x=4

x=4/-15

x=-4/15

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