2x-8+6x=8(2x-3)2x-8+6x=16x-248+8x=16x-2432=8x4=x

Solution for 2x-8+6x=8(2x-3)2x-8+6x=16x-248+8x=16x-2432=8x4=x equation:

2x-8+6x=8(2x-3)2x-8+6x=16x-248+8x=16x-2432=8x^4=x

We move all terms to the left:

2x-8+6x-(8(2x-3)2x-8+6x)=0

We add all the numbers together, and all the variables

8x-(8(2x-3)2x-8+6x)-8=0


We calculate terms in parentheses: -(8(2x-3)2x-8+6x), so:

8(2x-3)2x-8+6x

determiningTheFunctionDomain
8(2x-3)2x+6x-8

We add all the numbers together, and all the variables

6x+8(2x-3)2x-8

We multiply parentheses

32x^2+6x-48x-8

We add all the numbers together, and all the variables

32x^2-42x-8

Back to the equation:

-(32x^2-42x-8)


We get rid of parentheses

-32x^2+8x+42x+8-8=0

We add all the numbers together, and all the variables

-32x^2+50x=0

a = -32; b = 50; c = 0;
Δ = b2-4ac
Δ = 502-4·(-32)·0
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2500}=50$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-50}{2*-32}=\frac{-100}{-64}
=1+9/16
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+50}{2*-32}=\frac{0}{-64}
=0
$