2x-8/8x+3=x-5/4x

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Solution for 2x-8/8x+3=x-5/4x equation: 



2x-8/8x+3=x-5/4x

We move all terms to the left:

2x-8/8x+3-(x-5/4x)=0



Domain of the equation: 8x!=0

x!=0/8

x!=0

x∈R





Domain of the equation: 4x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

2x-8/8x-(+x-5/4x)+3=0

We get rid of parentheses

2x-8/8x-x+5/4x+3=0

We calculate fractions


2x-x+(-32x)/32x^2+40x/32x^2+3=0

We add all the numbers together, and all the variables

x+(-32x)/32x^2+40x/32x^2+3=0

We multiply all the terms by the denominator


x*32x^2+(-32x)+40x+3*32x^2=0

We add all the numbers together, and all the variables

40x+x*32x^2+(-32x)+3*32x^2=0

Wy multiply elements

32x^3+96x^2+40x+(-32x)=0

We get rid of parentheses

32x^3+96x^2+40x-32x=0

We do not support expression: x^3

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