2x-8/x-3=0

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Solution for 2x-8/x-3=0 equation:



2x-8/x-3=0
Domain of the equation: x!=0
x∈R
We multiply all the terms by the denominator
2x*x-3*x-8=0
We add all the numbers together, and all the variables
-3x+2x*x-8=0
Wy multiply elements
2x^2-3x-8=0
a = 2; b = -3; c = -8;
Δ = b2-4ac
Δ = -32-4·2·(-8)
Δ = 73
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{73}}{2*2}=\frac{3-\sqrt{73}}{4} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{73}}{2*2}=\frac{3+\sqrt{73}}{4} $

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