2x-8=1-3(x-2)

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Solution for 2x-8=1-3(x-2) equation: 



2x-8=1-3(x-2)

We move all terms to the left:

2x-8-(1-3(x-2))=0



We calculate terms in parentheses: -(1-3(x-2)), so:

1-3(x-2)

determiningTheFunctionDomain
-3(x-2)+1

We multiply parentheses

-3x+6+1

We add all the numbers together, and all the variables

-3x+7

Back to the equation:

-(-3x+7)



We get rid of parentheses

2x+3x-7-8=0

We add all the numbers together, and all the variables

5x-15=0

We move all terms containing x to the left, all other terms to the right

5x=15

x=15/5

x=3

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