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2x-8=3(x-1)-2x
We move all terms to the left:
2x-8-(3(x-1)-2x)=0
We calculate terms in parentheses: -(3(x-1)-2x), so:We get rid of parentheses
3(x-1)-2x
We add all the numbers together, and all the variables
-2x+3(x-1)
We multiply parentheses
-2x+3x-3
We add all the numbers together, and all the variables
x-3
Back to the equation:
-(x-3)
2x-x+3-8=0
We add all the numbers together, and all the variables
x-5=0
We move all terms containing x to the left, all other terms to the right
x=5
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