2x-9/3x+4=-1

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Solution for 2x-9/3x+4=-1 equation:



2x-9/3x+4=-1
We move all terms to the left:
2x-9/3x+4-(-1)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
We add all the numbers together, and all the variables
2x-9/3x+5=0
We multiply all the terms by the denominator
2x*3x+5*3x-9=0
Wy multiply elements
6x^2+15x-9=0
a = 6; b = 15; c = -9;
Δ = b2-4ac
Δ = 152-4·6·(-9)
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{441}=21$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-21}{2*6}=\frac{-36}{12} =-3 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+21}{2*6}=\frac{6}{12} =1/2 $

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