2x-Ix+1I=5

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Solution for 2x-Ix+1I=5 equation:


Simplifying
2x + -1Ix + 1I = 5

Reorder the terms:
1I + 2x + -1xI = 5

Solving
1I + 2x + -1xI = 5

Solving for variable 'I'.

Move all terms containing I to the left, all other terms to the right.

Add '-2x' to each side of the equation.
1I + 2x + -2x + -1xI = 5 + -2x

Combine like terms: 2x + -2x = 0
1I + 0 + -1xI = 5 + -2x
1I + -1xI = 5 + -2x

Reorder the terms:
-5 + 1I + 2x + -1xI = 5 + -2x + -5 + 2x

Reorder the terms:
-5 + 1I + 2x + -1xI = 5 + -5 + -2x + 2x

Combine like terms: 5 + -5 = 0
-5 + 1I + 2x + -1xI = 0 + -2x + 2x
-5 + 1I + 2x + -1xI = -2x + 2x

Combine like terms: -2x + 2x = 0
-5 + 1I + 2x + -1xI = 0

The solution to this equation could not be determined.

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