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2x-x2=0.51
We move all terms to the left:
2x-x2-(0.51)=0
We add all the numbers together, and all the variables
-1x^2+2x-0.51=0
a = -1; b = 2; c = -0.51;
Δ = b2-4ac
Δ = 22-4·(-1)·(-0.51)
Δ = 1.96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-\sqrt{1.96}}{2*-1}=\frac{-2-\sqrt{1.96}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+\sqrt{1.96}}{2*-1}=\frac{-2+\sqrt{1.96}}{-2} $
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