2x/(x+3)=5-6/(x+3)

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Solution for 2x/(x+3)=5-6/(x+3) equation: 


D( x )

x+3 = 0

x+3 = 0

x+3 = 0

x+3 = 0 // - 3

x = -3

x in (-oo:-3) U (-3:+oo)

(2*x)/(x+3) = 5-(6/(x+3)) // - 5-(6/(x+3))

(2*x)/(x+3)+6/(x+3)-5 = 0

(2*x)/(x+3)+6/(x+3)+(-5*(x+3))/(x+3) = 0

2*x-5*(x+3)+6 = 0

2*x-5*x-15+6 = 0

-3*x-9 = 0

(-3*x-9)/(x+3) = 0

(-3*x-9)/(x+3) = 0 // * x+3

-3*x-9 = 0

-3*x-9 = 0 // + 9

-3*x = 9 // : -3

x = 9/(-3)

x = -3

x in { -3} 

x belongs to the empty set

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