2x/(x-2)=x/(x+1)

Solution for 2x/(x-2)=x/(x+1) equation:

2x/(x-2)=x/(x+1)

We move all terms to the left:

2x/(x-2)-(x/(x+1))=0


Domain of the equation: (x-2)!=0

We move all terms containing x to the left, all other terms to the right

x!=2

x∈R



Domain of the equation: (x+1))!=0

x∈R


We calculate fractions


4x^2/((x-2)*(x+1)))+(-(x*(x-2))/((x-2)*(x+1)))=0


We calculate terms in parentheses: -(x*(x-2))/((x-2)*(x+1))), so:

x*(x-2))/((x-2)*(x+1))

We multiply all the terms by the denominator


x*(x-2))

We multiply parentheses

x^2-2x^2

We add all the numbers together, and all the variables

-1x^2

Back to the equation:

-(-1x^2)


We get rid of parentheses

4x^2/((x-2)*(x+1)))+(+1x^2=0

We multiply all the terms by the denominator


4x^2+1x^2*((x-2)*(x+1)))+(=0