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2x/(x-3)(x+5)=0
Domain of the equation: (x-3)(x+5)!=0We multiply parentheses ..
We move all terms containing x to the left, all other terms to the right
x-3)(x!=-5
x∈R
2x/(+x^2+5x-3x-15)=0
We multiply all the terms by the denominator
2x=0
x=0/2
x=0
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