2x/2=(x+1)/5

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Solution for 2x/2=(x+1)/5 equation: 



2x/2=(x+1)/5

We move all terms to the left:

2x/2-((x+1)/5)=0

We calculate fractions


10x^2/()+(-((x+1)*2)/()=0



We calculate terms in parentheses: +(-((x+1)*2)/(), so:

-((x+1)*2)/(

We multiply all the terms by the denominator


-((x+1)*2)



We calculate terms in parentheses: -((x+1)*2), so:

(x+1)*2

We multiply parentheses

2x+2

Back to the equation:

-(2x+2)



We get rid of parentheses

-2x-2

Back to the equation:

+(-2x-2)



We get rid of parentheses

10x^2/()-2x-2=0

We multiply all the terms by the denominator


10x^2-2x*()-2*()=0

We add all the numbers together, and all the variables

10x^2-2x*()=0

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