2x/3+1=1/6(6+4x)

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Solution for 2x/3+1=1/6(6+4x) equation: 



2x/3+1=1/6(6+4x)

We move all terms to the left:

2x/3+1-(1/6(6+4x))=0



Domain of the equation: 6(6+4x))!=0

x∈R



We add all the numbers together, and all the variables

2x/3-(1/6(4x+6))+1=0

We calculate fractions


(12x^24/(18x4+()/(18x4+1=0

We do not support expression: x^24

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