2x/3+x/2=1/6,x=

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Solution for 2x/3+x/2=1/6,x= equation: 



2x/3+x/2=1/6.x=

We move all terms to the left:

2x/3+x/2-(1/6.x)=0



Domain of the equation: 6.x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

2x/3+x/2-(+1/6.x)=0

We get rid of parentheses

2x/3+x/2-1/6.x=0

We calculate fractions

There is no solution for this equation

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