2x/3+y/5=6;x/6-y/2=-4

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Solution for 2x/3+y/5=6;x/6-y/2=-4 system of equations: 


  • /| (2*x)/3+y/5-6 = 0| x/6-(y/2)+4 = 0
  • We try to solve the equation: (2*x)/3+y/5-6 = 0
  • 2/3*x+1/5*y-6 = 0 // - 2/3*x-6
  • 1/5*y = -(2/3*x-6) // : 1/5
  • y = (-(2/3*x-6))/1/5
  • y = 5*(6-(2/3*x))
  • We insert the solution into one of the initial equations of our system of equations
  • We get a system of equations:
  • /| x/6-((5*(6-(2/3*x)))/2)+4 = 0| y = 5*(6-(2/3*x))
  • (-1*5*(6-2/3*x))/2+x/6+4 = 0
  • 11/6*x-15+4 = 0
  • 11/6*x-11 = 0
  • 11/6*x-11 = 0 // + 11
  • 11/6*x = 11 // : 11/6
  • x = 11/11/6
  • x = 6
  • We insert the solution into one of the initial equations of our system of equations
  • For y = 5*(6-(2/3*x)): 
  • y = 5*(6-(2/3*6))
  • y = 5*(6-4)
  • y = 2*5
  • y = 10
  • We get a system of equations:
  • /| y = 10| x = 6

 

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