2x/3-19=-x+10

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Solution for 2x/3-19=-x+10 equation:



2x/3-19=-x+10
We move all terms to the left:
2x/3-19-(-x+10)=0
We add all the numbers together, and all the variables
2x/3-(-1x+10)-19=0
We get rid of parentheses
2x/3+1x-10-19=0
We multiply all the terms by the denominator
2x+1x*3-10*3-19*3=0
We add all the numbers together, and all the variables
2x+1x*3-87=0
Wy multiply elements
2x+3x-87=0
We add all the numbers together, and all the variables
5x-87=0
We move all terms containing x to the left, all other terms to the right
5x=87
x=87/5
x=17+2/5

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