2x/3=(x/2)+20

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Solution for 2x/3=(x/2)+20 equation: 



2x/3=(x/2)+20

We move all terms to the left:

2x/3-((x/2)+20)=0

We add all the numbers together, and all the variables

2x/3-((+x/2)+20)=0

We calculate fractions


4x^2/()+(-((+x*3)/()=0



We calculate terms in parentheses: +(-((+x*3)/(), so:

-((+x*3)/(

We multiply all the terms by the denominator


-((+x*3)



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(+x*3





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(+x*3





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(+x*3





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(+x*3





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(+x*3





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(+x*3





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(+x*3





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(+x*3





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(+x*3





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(+x*3





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(+x*3





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(+x*3





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(+x*3





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(+x*3





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(+x*3





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(+x*3





We calculate terms in parentheses: -((+x*3), so:

(+x*3





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(+x*3





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(+x*3





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(+x*3





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(+x*3





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(+x*3





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(+x*3





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(+x*3





We calculate terms in parentheses: -((+x*3), so:

(+x*3





We calculate terms in parentheses: -((+x*3), so:

(+x*3





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(+x*3





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(+x*3





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(+x*3





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(+x*3





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(+x*3





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(+x*3





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(+x*3





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(+x*3





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(+x*3





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(+x*3





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(+x*3





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(+x*3





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(+x*3





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(+x*3





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(+x*3





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(+x*3





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(+x*3





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(+x*3





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(+x*3





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(+x*3





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(+x*3





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(+x*3





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(+x*3





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(+x*3





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(+x*3



Back to the equation:

+(-((+x*3))



We multiply all the terms by the denominator


4x^2+((-((+x*3)))*()=0



We calculate terms in parentheses: +((-((+x*3)))*(), so:

(-((+x*3)))*(





We calculate terms in parentheses: +((-((+x*3)))*(), so:

(-((+x*3)))*(





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(-((+x*3)))*(





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(-((+x*3)))*(





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(-((+x*3)))*(





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(-((+x*3)))*(





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(-((+x*3)))*(





We calculate terms in parentheses: +((-((+x*3)))*(), so:

(-((+x*3)))*(





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(-((+x*3)))*(





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(-((+x*3)))*(





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(-((+x*3)))*(





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(-((+x*3)))*(





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(-((+x*3)))*(





We calculate terms in parentheses: +((-((+x*3)))*(), so:

(-((+x*3)))*(





We calculate terms in parentheses: +((-((+x*3)))*(), so:

(-((+x*3)))*(





We calculate terms in parentheses: +((-((+x*3)))*(), so:

(-((+x*3)))*(





We calculate terms in parentheses: +((-((+x*3)))*(), so:

(-((+x*3)))*(





							

									
									
									
									
									
									

														
			

			
				

						
				
				
					
			
						
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