2x/3=10-(24/x)

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Solution for 2x/3=10-(24/x) equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(2*x)/3 = 10-(24/x) // - 10-(24/x)

(2*x)/3+24/x-10 = 0

2/3*x^1+24*x^-1-10*x^0 = 0

(2/3*x^2-10*x^1+24*x^0)/(x^1) = 0 // * x^2

x^1*(2/3*x^2-10*x^1+24*x^0) = 0

x^1

(2/3)*x^2-10*x+24 = 0

(2/3)*x^2-10*x+24 = 0

DELTA = (-10)^2-(4*24*(2/3))

DELTA = 36

DELTA > 0

x = (36^(1/2)+10)/(2*(2/3)) or x = (10-36^(1/2))/(2*(2/3))

x = 12 or x = 3

x in { 3, 12} 

x in { 3, 12 }

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