2x/3x+1=3x/5x

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Solution for 2x/3x+1=3x/5x equation:



2x/3x+1=3x/5x
We move all terms to the left:
2x/3x+1-(3x/5x)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 5x)!=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
2x/3x-(+3x/5x)+1=0
We get rid of parentheses
2x/3x-3x/5x+1=0
We calculate fractions
(-9x^2)/15x^2+10x^2/15x^2+1=0
We multiply all the terms by the denominator
(-9x^2)+10x^2+1*15x^2=0
We add all the numbers together, and all the variables
10x^2+(-9x^2)+1*15x^2=0
Wy multiply elements
10x^2+(-9x^2)+15x^2=0
We get rid of parentheses
10x^2-9x^2+15x^2=0
We add all the numbers together, and all the variables
16x^2=0
a = 16; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·16·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{32}=0$

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