2x/3x=3x/4x+3

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Solution for 2x/3x=3x/4x+3 equation: 



2x/3x=3x/4x+3

We move all terms to the left:

2x/3x-(3x/4x+3)=0



Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R





Domain of the equation: 4x+3)!=0

x∈R



We get rid of parentheses

2x/3x-3x/4x-3=0

We calculate fractions


(-9x^2)/12x^2+8x^2/12x^2-3=0

We multiply all the terms by the denominator


(-9x^2)+8x^2-3*12x^2=0

We add all the numbers together, and all the variables

8x^2+(-9x^2)-3*12x^2=0

Wy multiply elements

8x^2+(-9x^2)-36x^2=0

We get rid of parentheses

8x^2-9x^2-36x^2=0

We add all the numbers together, and all the variables

-37x^2=0

a = -37; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-37)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-74}=0$

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