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((2*x)/3)*x = x/15-(6/5) // - x/15-(6/5)
((2*x)/3)*x-(x/15)+6/5 = 0
2/3*x^2-1/15*x+6/5 = 0
DELTA = (-1/15)^2-(2/3*6/5*4)
DELTA = -719/225
DELTA < 0
x belongs to the empty set
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