2x/4x=3x/18

Solution for 2x/4x=3x/18 equation:

2x/4x=3x/18

We move all terms to the left:

2x/4x-(3x/18)=0


Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R


We add all the numbers together, and all the variables

2x/4x-(+3x/18)=0

We get rid of parentheses

2x/4x-3x/18=0

We calculate fractions


(-12x^2)/72x+36x/72x=0

We multiply all the terms by the denominator


(-12x^2)+36x=0

We get rid of parentheses

-12x^2+36x=0

a = -12; b = 36; c = 0;
Δ = b2-4ac
Δ = 362-4·(-12)·0
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-36}{2*-12}=\frac{-72}{-24}
=+3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+36}{2*-12}=\frac{0}{-24}
=0
$