2x/5=(1/3)2x-12

Solution for 2x/5=(1/3)2x-12 equation:

2x/5=(1/3)2x-12

We move all terms to the left:

2x/5-((1/3)2x-12)=0


Domain of the equation: 3)2x-12)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

2x/5-((+1/3)2x-12)=0

We calculate fractions


6x^2/15x+()/15x=0

We multiply all the terms by the denominator


6x^2+()=0

We add all the numbers together, and all the variables

6x^2=0

a = 6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·6·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{12}=0$