2x/5=(12/10)

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Solution for 2x/5=(12/10) equation:



2x/5=(12/10)
We move all terms to the left:
2x/5-((12/10))=0
We add all the numbers together, and all the variables
2x/5-((+12/10))=0
We calculate fractions
20x^2/()+()/()=0
We add all the numbers together, and all the variables
20x^2/()+1=0
We multiply all the terms by the denominator
20x^2+1*()=0
We add all the numbers together, and all the variables
20x^2=0
a = 20; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·20·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{40}=0$

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