2x/5=(5x+2)/6

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Solution for 2x/5=(5x+2)/6 equation: 



2x/5=(5x+2)/6

We move all terms to the left:

2x/5-((5x+2)/6)=0

We calculate fractions


12x^2/()+(-((5x+2)*5)/()=0



We calculate terms in parentheses: +(-((5x+2)*5)/(), so:

-((5x+2)*5)/(

We multiply all the terms by the denominator


-((5x+2)*5)



We calculate terms in parentheses: -((5x+2)*5), so:

(5x+2)*5

We multiply parentheses

25x+10

Back to the equation:

-(25x+10)



We get rid of parentheses

-25x-10

Back to the equation:

+(-25x-10)



We get rid of parentheses

12x^2/()-25x-10=0

We multiply all the terms by the denominator


12x^2-25x*()-10*()=0

We add all the numbers together, and all the variables

12x^2-25x*()=0

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