2x/5=(X+4)/2

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Solution for 2x/5=(X+4)/2 equation: 



2x/5=(x+4)/2

We move all terms to the left:

2x/5-((x+4)/2)=0

We calculate fractions


4x^2/()+(-((x+4)*5)/()=0



We calculate terms in parentheses: +(-((x+4)*5)/(), so:

-((x+4)*5)/(

We multiply all the terms by the denominator


-((x+4)*5)



We calculate terms in parentheses: -((x+4)*5), so:

(x+4)*5

We multiply parentheses

5x+20

Back to the equation:

-(5x+20)



We get rid of parentheses

-5x-20

Back to the equation:

+(-5x-20)



We get rid of parentheses

4x^2/()-5x-20=0

We multiply all the terms by the denominator


4x^2-5x*()-20*()=0

We add all the numbers together, and all the variables

4x^2-5x*()=0

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