2x/6-x/3=2/5

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Solution for 2x/6-x/3=2/5 equation: 


x in (-oo:+oo)

(2*x)/6-(x/3) = 2/5 // - 2/5

(2*x)/6-(x/3)-(2/5) = 0

(2*x)/6-(x/3)-2/5 = 0

-2/5 = 0

x belongs to the empty set

x belongs to the empty set

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